generated from kenryuS/report-temp
2026/05/16
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\section{実験条件・手順}
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\subsection{実験器具}
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今回の実験では以下の器具を用いた:
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\begin{itemize}
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\item{ブレッドボード Sunhayato SHR-74}
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\item{デジタルマルチメータ SANWA PC700}
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\item{直流安定化電源 KENWOOD PR18-1.2A}
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\item{抵抗器 $1.0 \ \text{k}\Omega \pm 5\%$, 1/4 W}
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\item{抵抗器 $2.2 \ \text{k}\Omega \pm 5\%$, 1/4 W}
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\item{抵抗器 $3.3 \ \text{k}\Omega \pm 5\%$, 1/4 W}
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\end{itemize}
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\subsection{実験1}
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\begin{enumerate}
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\item{\cref{fig:cd-exp1}の回路をブレッドボード上で作成する}
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\item{3種類の抵抗$(R = 1.0 \ \text{k}\Omega, 2.2 \ \text{k}\Omega, 3.3 \ \text{k}\Omega)$について,3つの電源電圧$(E = 3 \ \text{V}, 6 \ \text{V}, 9 \ \text{V})$}における\\電流を測定する
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\end{enumerate}
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\begin{figure}[tbh]
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\centering
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\begin{circuitikz}
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\draw (0,3) to [cvsourceAM, l=$E$] (0,0);
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\draw (0,3) to [rmeterwa, t=A] (3,3) to [R, l=$R$] (3,0) -- (0,0);
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\draw (3,3) to [short, *-] ++(2,0) to [rmeterwa, t=V, straight instruments] ++(0,-3) to [short, -*] ++(-2,0);
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\draw (0,0) node[ground]{} ++(0,-0.5);
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\end{circuitikz}
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\caption{Circuit Diagram of Experiment \# 1}
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\label{fig:cd-exp1}
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\end{figure}
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\subsection{実験2}
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\begin{enumerate}
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\item{\cref{fig:cd-exp2-a}の回路を作成し,電流$I_1, I_2, I_3$,抵抗$R_1, R_2, R_3$の端子間電圧$V_1, V_2, V_3$および電源電圧$E_1, E_2$を測定する}
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\item{\cref{fig:cd-exp2-b}の回路を作成し,1. 同様に測定する}
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\end{enumerate}
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\begin{figure}[tbh]
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\centering
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\begin{minipage}[h]{0.90\linewidth}
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\centering
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\begin{circuitikz}
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\draw (0,3) node[above]{a} to [cvsourceAM, l_={$E_1=15 \ \text{V}$}] (0,0) node[left]{f};
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\draw (0,3) to [R, l={$R_1$}, a={$3.3 \ \text{k}\Omega$}, i_={$I_1$}] ++(3,0) node[above]{b};
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\draw (6,3) node[above]{c} to [cvsourceAM, l={$E_2=3 \ \text{V}$}] (6,0) node[right]{d};
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\draw (6,3) to [R, l_={$R_2$}, a^={$1.0 \ \text{k}\Omega$}, i={$I_2$}] ++(-3,0);
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\draw (3,3) node[circ]{} to [R, l={$R_3$}, a={$2.2 \ \text{k}\Omega$}, i={$I_3$}] ++(0,-3) node[circ]{} node[below]{e};
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\draw (6,0) to [short,-*] (0,0);
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\draw (0,0) node[ground]{} ++(0,-0.5);
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\end{circuitikz}
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\subcaption{Circuit (a)}
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\label{fig:cd-exp2-a}
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\end{minipage}
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\begin{minipage}[h]{0.90\linewidth}
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\centering
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\begin{circuitikz}
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\draw (0,3) node[above]{a} to [cvsourceAM, l_={$E_1=15 \ \text{V}$}] (0,0) node[left]{f};
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\draw (0,3) to [R, l={$R_1$}, a={$3.3 \ \text{k}\Omega$}, i_={$I_1$}] ++(3,0) node[above]{b};
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\draw (6,0) node[right]{d} to [cvsourceAM, l_={$E_2=3 \ \text{V}$}] (6,3) node[above]{c};
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\draw (6,3) to [R, l_={$R_2$}, a^={$1.0 \ \text{k}\Omega$}, i={$I_2$}] ++(-3,0);
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\draw (3,3) node[circ]{} to [R, l={$R_3$}, a={$2.2 \ \text{k}\Omega$}, i={$I_3$}] ++(0,-3) node[circ]{} node[below]{e};
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\draw (6,0) to [short,-*] (0,0);
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\draw (0,0) node[ground]{} ++(0,-0.5);
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\end{circuitikz}
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\subcaption{Circuit (b)}
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\label{fig:cd-exp2-b}
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\end{minipage}
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\caption{Circuit Diagrams of Experiment \# 2}
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\label{fig:cd-exp2}
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\end{figure}
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\subsection{実験3}
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\begin{enumerate}
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\item{\cref{fig:cd-exp2-a}の回路を作成し,電流$I_1, I_2, I_3$,抵抗$R_1, R_2, R_3$の端子間電圧$V_1, V_2, V_3$および電源電圧$E_1, E_2$を測定する.この時,$E_2$を取り外し,短絡させる}
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\item{$E_2$を戻し,$E_1$を取り外し,短絡させ,1. 同様に測定する}
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\item{$E_1$を戻し,$E_1, E_2$同時に印加させ,1. 同様に測定する}
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\end{enumerate}
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なお今回の実験の手順3では実験2の手順1の結果を使用する.
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\subsection{実験4}
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\begin{enumerate}
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\item{\cref{fig:cd-exp4-oc}を\cref{fig:cd-exp4-ec}の等価回路で表す時,$V_t$と$R_t$を理論的に求める}
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\item{\cref{fig:cd-exp4-oc}の回路を作成し,負荷抵抗$R_L$の端子間電圧とそれに流れ込む電流を測定する}
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\item{\cref{fig:cd-exp4-ec}の回路を作成し,2. 同様に測定する.なお$R_t$には$10 \ \text{k}\Omega$の可変抵抗を使い,電源電圧も理論値$V_t$に設定する}
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\end{enumerate}
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\begin{figure}[tbh]
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\centering
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\begin{minipage}[h]{0.45\linewidth}
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\centering
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\begin{circuitikz}
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\draw (0,3) to [cvsourceAM, l_={$E_1 = 15 \ \text{V}$}] (0,0);
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\draw (0,3) to [R={$R_1$}, a={$3.3 \ \text{k}\Omega$}] ++(2,0) to [R={$R_2$}, a={$2.2 \ \text{k}\Omega$}] ++(0,-3) to [short, *-*] ++(-2,0);
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\draw (2,3) to [short, *-o] ++(1,0) node[above]{A} -- ++(1,0) to [R={$R_L$}, a={$1 \ \text{k}\Omega$}] ++(0,-3) -- ++(-1,0) node[above]{B} to [short, o-] ++(-1,0);
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\draw (0,0) to node[ground]{} ++(0,-0.5);
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\end{circuitikz}
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\subcaption{Original Circuit}
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\label{fig:cd-exp4-oc}
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\end{minipage}
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\begin{minipage}[h]{0.45\linewidth}
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\centering
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\begin{circuitikz}
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\draw (0,3) to [cvsourceAM, l={$V_t$}] (0,0);
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\draw (0,3) to [R={$R_t$}] ++(2,0) to [short, -o] ++(1,0) node[above]{A} -- ++(1,0) to [R={$R_L$}, a={$1 \ \text{k}\Omega$}] ++(0,-3) -- ++(-1,0) node[above]{B} to [short, o-*] ++(-3,0);
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\draw (0,0) to node[ground]{} ++(0,-0.5);
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\end{circuitikz}
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\subcaption{Equivalent Circuit}
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\label{fig:cd-exp4-ec}
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\end{minipage}
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\caption{Circuit Diagrams of Experiment \# 4}
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\label{fig:cd-exp4}
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\end{figure}
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+106
-23
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\subsection{実験1}
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それぞれの抵抗の理論値と実測値を\cref{fig:v-i-r}に示す.なお,理論値には$\pm 5\%$の誤差の範囲も同時に表示している.
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\begin{figure}[tbh]
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\centering
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\input{assets/a-2/exp1}
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\caption{Voltage v.s. Current of Differenct Resistors with Theoretical Values and Error Ranges}
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\label{fig:v-i-r}
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\end{figure}
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\newpage
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\subsection{実験2}
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\subsubsection{回路1}
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\subsubsection{回路(a)}
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At E1 = 15.000, E2 = 3.005
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$E_1 = 15.000 \ \text{V}, \ E_2 = 3.005 \ \text{V}$の時,各抵抗での電流・電圧は\cref{tab:exp2-res1}となった:
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I1 = -3.28m, V1 = 10.69
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I2 = 1.31m, V2 = 1.296
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I3 = 1.98m, V3 = 4.297
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%I1 = -3.28m, V1 = 10.69
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%I2 = 1.31m, V2 = 1.296
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%I3 = 1.98m, V3 = 4.297
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\subsubsection{回路2}
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\begin{table}[ht]
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\centering
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\caption{Result of Experiment \# 2 with Circuit (a)}
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\label{tab:exp2-res1}
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\begin{tabular}{c|c|c}
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\hline
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Resistor & Voltage $[\text{V}]$ & Current $[\text{mA}]$ \\
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\hline
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$R_1$ & 10.69 & -3.28 \\
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$R_2$ & 1.30 & 1.31 \\
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$R_3$ & 4.30 & 1.98 \\
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\hline
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\end{tabular}
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\end{table}
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At E1 = 15.000, E2 = -3.007
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\subsubsection{回路(b)}
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I1 = 4.33m, V1 = 14.10
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I2 = -3.93m, V2 = -3.891
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I3 = -0.40m, V3 = 0.890
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$E_1 = 15.000 \ \text{V}, \ E_2 = -3.007 \ \text{V}$の時,各抵抗での電流・電圧は\cref{tab:exp2-res2}となった:
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%I1 = 4.33m, V1 = 14.10
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%I2 = -3.93m, V2 = -3.891
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%I3 = -0.40m, V3 = 0.890
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\begin{table}[ht]
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\centering
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\caption{Result of Experiment \# 2 with Circuit (b)}
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\label{tab:exp2-res2}
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\begin{tabular}{c|c|c}
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\hline
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Resistor & Voltage $[\text{V}]$ & Current $[\text{mA}]$ \\
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\hline
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$R_1$ & 14.10 & 4.33 \\
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$R_2$ & -3.89 & -3.93 \\
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$R_3$ & 0.89 & 0.40 \\
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\hline
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\end{tabular}
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\end{table}
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\subsection{実験3}
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\subsubsection{E1 only}
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\subsubsection{$E_1$のみ}
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At E1 = 15.000
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$E_1 = 15.000 \ \text{V}$での各抵抗にかかった電流・電圧は\cref{tab:exp3-res1}となった:
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I1 = 3.81m, V1 = 12.40
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I2 = 2.61m, V2 = 2.596
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I3 = 1.19m, V3 = 2.593
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%I1 = 3.81m
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%I2 = 2.61m
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%I3 = 1.19m
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%V1 = 12.40
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%V2 = 2.596
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%V3 = 2.593
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\subsubsection{E2 only}
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\begin{table}[ht]
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\centering
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\caption{Result of Experiment \# 3 with $E_1$ as Voltage Source}
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\label{tab:exp3-res1}
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\begin{tabular}{c|c|c}
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\hline
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Resistor & Voltage $[\text{V}]$ & Current $[\text{mA}]$ \\
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\hline
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$R_1$ & 12.40 & 3.81 \\
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$R_2$ & 2.61 & 2.61 \\
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$R_3$ & 2.59 & 1.19 \\
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\hline
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\end{tabular}
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\end{table}
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At E2 = 3.004
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\subsubsection{$E_2$のみ}
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I1 = 0.52m, V1 = -1.705
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I2 = 1.31m, V2 = -1.294
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I3 = 0.78m, V3 = 1.704
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$E_2 = 3.004 \ \text{V}$での各抵抗にかかった電流・電圧は\cref{tab:exp3-res2}となった:
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\begin{table}[ht]
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\centering
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\caption{Result of Experiment \# 3 with $E_2$ as Voltage Source}
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\label{tab:exp3-res2}
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\begin{tabular}{c|c|c}
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\hline
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Resistor & Voltage $[\text{V}]$ & Current $[\text{mA}]$ \\
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\hline
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$R_1$ & 1.71 & 0.52 \\
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$R_2$ & 1.29 & 1.32 \\
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$R_3$ & 1.70 & 0.78 \\
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\hline
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\end{tabular}
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\end{table}
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\subsection{実験4}
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Calculated value: R_t = \frac{R_{1} R_{2}}{R_1 + R_2} = 1320, V_t = \frac{R_{2}E_{1}}{R_1 + R_2} = 6
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%Calculated value: R_t = \frac{R_{1} R_{2}}{R_1 + R_2} = 1320, V_t = \frac{R_{2}E_{1}}{R_1 + R_2} = 6
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without vr: 2.595V, 2.62mA
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with vr:
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等価回路でのパラメータの値は$V_{t} = 6 \ \text{V}, \ R_{t} = 1320 \ \Omega$となった.これらの値に元にした実験の結果を\cref{tab:exp4-res}にまとめる.
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\begin{table}[htb]
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\centering
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\caption{Voltage and Current of Load}
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\label{tab:exp4-res}
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\begin{tabular}{c|c|c}
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\hline
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Circuit & Voltage $[\text{V}]$ & Current $[\text{mA}]$ \\
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\hline
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Original Circuit & 2.595 & 2.62 \\
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Replaced with Variable Resistor & 2.576 & 2.61 \\
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\hline
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\end{tabular}
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\end{table}
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%without vr: 2.595V, 2.62mA
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%with vr: 2.576V, 2.61mA
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\section{考察}
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\section{理論}
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\subsection{オームの法則}
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ある抵抗値を持つ抵抗器$R \ [\Omega]$に対し電圧$V \ [\text{V}]$を印加すると抵抗に電流$I \ [\text{A}]$が流れる.
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この時,$V, R, I$には次の関係式が成り立つ.
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\begin{equation}\label{equ:ohm}
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V = RI
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\end{equation}
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\cref{equ:ohm}で表されるこの関係をオームの法則という.
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電圧は電流に比例するのでV-I図は\cref{fig:v-i-example}のようになる.
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\begin{figure}[tbh]
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\centering
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\begin{tikzpicture}[domain=0:4]
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\draw[->] (0,0) -- (4.5,0);
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\draw[->] (0,0) -- (0,4.5);
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\foreach \x in {0,...,4} {
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\draw (\x, 0) node[below]{\x} -- (\x, 0.1);
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\draw (0, \x) node[left]{\x} -- (0.1, \x);
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}
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\draw plot (\x, \x) node[left=5pt]{$R = 1 \ \text{k}\Omega$};
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\draw plot (\x, {\x/2}) node[below=10pt]{$R = 2 \ \text{k}\Omega$};
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\node at (2.25,-0.4) [below] {Voltage [V]};
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\node[rotate=90] at (-0.3,2.25) [above] {Current [mA]};
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\end{tikzpicture}
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\caption{Ohm's Law on Graph}
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\label{fig:v-i-example}
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\end{figure}
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\subsection{キルヒホッフの法則}
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複数の抵抗・電源からなる複雑な回路はオームの法則だけでは回路を解くことはできない.
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キルヒホッフの法則はそのような回路網を計算する際に用いられる.
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この法則には2つの性質が定義されている.
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第一法則は電流則とも呼ばれ,回路中の接点の電流の入出流の関係が定義されている.
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第二法則は電圧則とも呼ばれ,
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\subsection{重ね合わせの理}
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\subsection{テブナンの定理}
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